Four Bit Adder Subtractor

Binary addition is certainly easier than decimal addition. You just add 0s and 1s. For example to add the numbers five (0101) and six (0110) together, we just add the respective bits:

Decimal numerals	Binary numerals
6 +5	0110 +0101
11	1011

For binary subtraction, we use 2’s complement to keep things simple. For instance, to perform the operation six (0110) minus five (0101), we first obtain the 2’s complement of five and then add it to six:

Step one: Getting the 2’s complement of 5

1. Flip every bit in five to get 1010.
2. Add one to 1010 to get: 1010 + 1 = 1011.

Step two: Adding the 2’s complement of 5 to 6:

1. Decimal numerals	Binary numerals
   6 +(-5)	0110 +1011
   1	10001.

We show the carry bit in green because normally it does not count towards the result.

Design

Now that we have reviewed our binary addition and subtraction skills, let’s look at what the circuit is doing. If you fix your gaze on the full–adders while you play around with the input switches, you will see that no matter what operation you think you are doing, the full–adder’s job never changes: the full–adder adds up the signals that appear at its inputs. This is surely not a strange behavior. In reality, whether you are doing binary addition or binary subtraction, the last thing you always do is add the numbers (e.g. “Step two” above tells you to add).

So how does the circuit know whether you want to add or subtract? The XOR gates and the Mode switch, of course! The circuit assumes that your subtraction will always be in the form A — B. So because one input of each XOR gate is attached to the Mode switch while the other input of each XOR gate is attached to a B bit, when the Mode switch is equal to 1, the output of the XOR is the complement of B. This is because B 0 = B and B 1 = B’. In addition to going into the XOR gates, the Mode signal also goes into the carry input of the least significant full–adder (C₀), which basically adds a 1 to B’ when the Mode switch is ON. Hence, when the Mode switch is equal to 1, the XOR gates and the Mode switch take the 2’s complement of B and pass it to the full–adders.

To recap, here is a brief summary of how the circuit works: When M = 0, the full–adders see A + B because B 0 = B. However, when M = 1, the full–adders see A + B’ + 1 because B 1 = B’ and C₀ = M. And, yes, (B’ + 1) is the 2’s complement of B.